1/2r=5/r^2+5/2r

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Solution for 1/2r=5/r^2+5/2r equation: 


D( r )

r^2 = 0

r^2 = 0

r^2 = 0

1*r^2 = 0 // : 1

r^2 = 0

r = 0

r in (-oo:0) U (0:+oo)

(1/2)*r = (5/2)*r+5/(r^2) // - (5/2)*r+5/(r^2)

(1/2)*r-((5/2)*r)-(5/(r^2)) = 0

(1/2)*r+(-5/2)*r-5*r^-2 = 0

-2*r-5*r^-2 = 0

-r*(5*r^-3+2) = 0

5*r^-3 = -2 // : 5

r^-3 = -2/5

-3 < 0

1/(r^3) = -2/5 // * r^3

1 = -2/5*r^3 // : -2/5

-5/2 = r^3

r^3 = -5/2 // ^ 1/3

r = -(5/2)^(1/3)

-r = 0

-1*r = 0 // : -1

r = 0

r in { 0} 

r = -(5/2)^(1/3)

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